1) consider the reariaus al the equabrikn lomitant at this a mlinare o S02 with

Question

1) consider the reariaus al the equabrikn lomitant at this a mlinare o S02 with presure atml and 02 a catalyst is afded the follamma reaction take place and the yalem at all mactants and proih and the reached equilibrium at a Dertain high temperature Origisaly, the eeaeson pantuned the dollawing the intenaity af the clar. Arequilibrun the No concentration had become .118 Whil is the value of Kefar the reaction Also determine the equilibrium concentratiens of N.0.0 and NO. 4) At 250 aC Dslu malou and 020 anol were placed in a 1000 L taiter where the following eq was established larium the Nor oncentration was 02gomoles waatisthe vlue ofthe far this reaction? Also deerrmine the coacentrasigm

Explanation / Answer

1. For the given reaction,

Keq = [S]^3.[H2O]^2/[SO2][H2S]^2

equilibrium,

[H2O] = 0.0011 M

[S] = 0.0011 x 3/2 = 0.00165 M

[H2S] = 0.5 - 0.0011 = 0.4989 M

[SO2] = 0.5 - 0.0011/2 = 0.49945 M

So,

Keq = 4.37 x 10^-14

3) For the reaction,

NO2 + NO --> N2O + O2

equilibrium concentrations of,

[NO2] = 0.118 M

change in concentration of NO2 = 0.118 - 0.056 = 0.062 M

So,

[NO] = 0.294 + 0.062 = 0.356 M

[N2O] = 0.184 - 0.062 = 0.122 M

[O2] = 0.377 - 0.062 = 0.315 M

Kc = 0.122 x 0.315/0.118 x 0.356 = 0.915

4. 2N2O + 3O2 --> 4NO2

Equilibrium,

[NO2] = 0.2 mol/10 L = 0.02 M

[N2O] = (0.20 - 0.02 x 2/4)/10 = 0.019 M

[O2] = (0.56 - 0.02 x 3/4)/10 = 0.0545 M

Kc = (0.02)^4/(0.019)^2.(0.0545)^3 = 2.74

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