How much heat is lost by the hot water? A. -3890J B. 4160J C 3890J D. -4160 J Ho

Question

How much heat is lost by the hot water?

A. -3890J

B. 4160J

C 3890J

D. -4160 J

How much heat was absorbed by cold water?

A. 4160J

B. 3890J

C. -4160J

D. -3890J

How much heat absorbed by the calorimeter?

A. 390J

B. -270J

C. 270J

D. -4160J

What is the delta T for Cold water? What is the delta T for hot water?

Experiment data:

Water bath is at a constant 60C

The initial temperature of the calorimeter is 21.5C

The mass of the cold water is 50g

When water 50g water was added to the calorimeter in the water bath the temperature was 39.6C

Explanation / Answer

Use the principle of thermochemistry

Heat lost by hot substance = heat gained by cold substance

We need to know the specific heat capacity of water, which is 4.186 J/g.C.

We had 50 g of cold water at 21.5C and the final temperature was 39.6C. Therefore, heat absorbed by cold water = (mass of cold water)*(specific heat capacity of cold water)*(change in temperature) = (50 g)*(4.186 J/g.C)*(39.6 – 21.5)C = 3788.33 J (ans).

The closest match is 3890; hence that is the answer.

Ans: (B) 3890 J

I need additional information like mass of hot water, mass of calorimeter and specific heat capacity of the calorimeter to answer the remaining questions.

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