How would your calculated value for the molecular weight of your unknown be affe

Question

How would your calculated value for the molecular weight of your unknown be affected (high, low, no effect) if a small quantity of the unknown stuck to the metal stirring rod and failed to dissolve in the benzophenone? Clearly explain your reasoning. When determining the melting point of your pure benzophenone, some of the molten material solidified high on the thermometer and wire stirrer. How would your calculated value for the molecular weight of your unknown been affected (high, low, no effect) if this benzophenone failed to melt and was not a part of the final mixture in the tube? Clearly explain your reasoning.

Explanation / Answer

1.The molecular weight of unknown will decrease if some amount of unknown sticks to metal stirring rod because this amount counts, when the weight is calculated as the metal stirring rod is still inside the benzophenone then .

But when this metal stirring rod is removed, that unknown which is stuck to it also comes out along with the rod. So the calculated weight is more, but the amount dissolved in benzophenone will br eventually less.

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