Only answers for D. Please explain, thank you! Use the Chem appendix on Sapling

Question

Only answers for D. Please explain, thank you! Use the Chem appendix on Sapling to find the K_a values for H_2CO_3. Now calculate the corresponding pK_a values and write BOTH next to the appropriate equilibrium reactions in part 1(a). If you wanted to go into the lab and emulate the buffer solution that exists in your blood which combination of compounds would you mix together to create your buffer? H_2CO_3 and KHCO_3 KHCO_3 and K_2CO_3 H_2CO_3 and K_2CO_3 EXPLAIN your choice: Which of the following, when mixed together would result in the formation of a buffer solution? Explain your answers in each case.

Explanation / Answer

buffer --> must be weak acid + conjugate base or vise vrsa

so..

CO3-2 and KHCO3 will form in solution:

HCO3- and CO3-2 which is the second ionization of H2CO3 acid

so this is a buffer

mmol of CO3 = 20*0.2 = 4

mmol of KHCO3 = 40*0.1 = 4 mmol

ratio is 4:4

For CO3-2 + KOH = no buffer formation, since storng base + weak base

for

H2CO3 + KHCO3 --< Expect

H2CO3 and HCO3- in solution, this is a buffer!

mmol of H2CO3 = 0.1*100 = 10

mmol of HCO3- = 0.4*0 = 4 mmol

raito is 4:10

for

KOH --> mmol of = 150*0.1 = 15 mmol of base

mmol of H2CO3 = 0.1*100 = 10 --> there is exces base, so no buffer forms

finally:

H+ and HCO3-

mmol ofHCO3- = 4

mmol of HCL = 2

thre will be H2CO3 and HCO3- present! this is a buffer

for KOH + HCl --> by definition, no bubber (strong acids/bases)

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