Could the separation in this experiment have been done in a different order? For
ID: 487520 • Letter: C
Question
Could the separation in this experiment have been done in a different order? For example, if the mixture was first extracted with water and then both the extract and the insoluble residue were heated to dryness, could you determine the amounts of NaCI, NH_4Cl, and SiO_2 originally present? Why or why not? Consult a handbook to answer these questions. How could your separate barium sulfate, BaSO_4, from NaCI? How could your separate magnesium chloride? MgCI_2, from silver chloride. AgCl? How could your separate tellurium dioxide, TeO_2, from SiO_2? How could you separate laurin acid from alpha-naphthol?Explanation / Answer
1. If the sample was weighed at the beginning & it was known that the sample contains NH4Cl, NaCl & SiO2 only then only it is possible . Extraction with water will dissolve both NaCl & NH4Cl leaving behind SiO2. Then heat the insoluble part to dryness & measure it . This will give us the amount of SiO2 that was originally present. If the liquid extract is heated to dryness then the volatile NH4Cl will escape with water leaving behind NaCl whose weight can be measured. The amount of NH4Cl is determined by the difference (It cannot be measured directly.)
2. Add water to the mixture & try to dissolve it. Nacl will get dissolved in water while BaSO4 will remain suspended so, it can be filtered & separated. while heat the liquid extract and after evaporation of water we will get NaCl.
3. Add water to this mixture also. MgCl2 is highly soluble in water while AgCl is insoluble in water & can be separated out by filtering and later heating.
4. Add Hydrofluoric acid HF to the mixture. TeO2 is neither soluble in water no in any acid while SiO2 is soluble in acid HF. Allow SiO2 to dissolve & decant the solution. Suspended solid will be SiO2.
5. Add cyclohexane to the mixture. alpha naphthol is insoluble in cyclohexane while lauric acid is soluble in cyclohexane.
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