Calculate the Fe(SCN) 2+ in the solution below, assuming that ALL of the SCN - p

Question

Calculate the Fe(SCN)2+ in the solution below, assuming that ALL of the SCN- present is combined in the complex ion, thus equilibrium moles of Fe(SCN)2+= initial moles of SCN-.

Fe3+ (aq) + SCN– (aq) FeSCN2+ (aq)

Beaker number

Calculate the Fe(SCN)2+ in the solution below, assuming that ALL of the SCN- present is combined in the complex ion, thus equilibrium moles of Fe(SCN)2+= initial moles of SCN-.

Fe3+ (aq) + SCN– (aq) FeSCN2+ (aq)

Beaker number

0.200 M Fe(NO3)3
(mL) 0.0020 M SCN–
(mL) H2O
(mL) Concentration Fe(SCN)+2 1 4.7 1.3 42.1

Explanation / Answer

So, assuming all SCN- will be combined..

then

ratio is 1:1

so

mmol of SCN- = MV = 0.002*1.3 = 0.0026 mmol of SCN-

then expect 0.0026 mmol of SCN to form Fe(SCN)+2

0.0026 mmol of Fe(SCN)+2

for concentration

[Fe(SCN)+2] = mmol/Vtotal = 0.0026 / (4.7+1.3+42.1) = 0.00005405405M

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