The following substances are either reactants or products, and are written in th

Question

The following substances are either reactants or products, and are written in the molecular form. Write the corresponding net ionic equations for the aqueous solution, in the correct direction (products on the right). If no clear direction can be predicted, please indicate. Example: Pbs + NaNO_3. The ions involved are Pb^2+, s^2-, Na^+, and No_3^-. We know from the solubility trend chart that all sulfides except Na^+, K^+ and NH_4^+ are insoluble, so that leaves PbS as a product. If we switch the ion partners we get the starting substances Pb(NO_3)_2 and Na_2S. The net ionic equation is Pb^2+ + S^2- rightarrow PbS a.HNO_3 + Ba(OH)_2 a._______________ b.HC_2H_3O_2 + K_2SO_4 b.______________ c. CO_2 + H_2O + NaCl c.____________________ d. NaOH + HI d.________________ e. PbSO_4 + Cu(NO_3)_2 e.____________________ f. HNO_3 + AgCl f.___________________ g. Ca(C_2H_3O_2)_2 + MgCl_2 g._____________________

Explanation / Answer

The products in the molecular form given are PbS and NaNO3 . Here PbS is insoluble and NaNO3 is soluble.

The starting materails are Pb(NO3)2 and Na2S. These tow substances are soluble.

Now we can easily write the complete moleculear equation,

Pb(NO3)2 (aq.) + Na2S (aq.) ------------------> PbS (s) + 2 NaNO3 (aq.)

Ionic equation:

Pb2+ (aq.) + 2 NO3- (aq.) + 2 Na+ (aq.) + S2- (aq.) -------> PbS (s) + 2 Na+ (aq.) + 2 NO3- (aq.)

Net ionic equation:

Pb2+ (aq.) + S2- (aq.) --------------------> PbS (s)

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