5. Calculate the vapor pressure of water over a solution of 78 grams of ethylene

Question

5. Calculate the vapor pressure of water over a solution of 78 grams of ethylene glycol, C2H6O2, dissolved in 122 mL of water at 23oC. Please show all work with the correct answer. Thank you!!! 5. Calculate the vapor pressure of water over a solution of 78 grams of ethylene glycol, C2H6O2, dissolved in 122 mL of water at 23oC. Please show all work with the correct answer. Thank you!!! 5. Calculate the vapor pressure of water over a solution of 78 grams of ethylene glycol, C2H6O2, dissolved in 122 mL of water at 23oC. Please show all work with the correct answer. Thank you!!!

Explanation / Answer

5)

mass of ethylene glycol = 78 grams

moles of ethylene glycol = 78 / 62.07

                                      = 1.257 mol

moles of water = 122 / 18 = 6.78 mol

mole fraction of ethylene glycol = 1.257 / (1.257 + 6.78)

                                                  = 0.1564

Po - Ps / Po = 0.1564

21.1 - Ps / 21.1 = 0.1564

Ps = 17.8 torr

vapour pressure of solution = 17.8 torr

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