For each of the reactions, calculate the mass (in grams) of the product formed w

Question

For each of the reactions, calculate the mass (in grams) of the product formed when 3.67 g of the underlined reactant completely reacts Assume that there is more than enough of the other reactant. Ba(s) + Cl_2(g) rightarrow BaCl_2(s) CaO(s) + CO_2(g) rightarrow CaCO_3(s) 2Mg(s) + O_2(s) rightarrow 2MgO(s) 4 Al(s) + 3 O_2(g) rightarrow 2 Al_2O_3(s) For each of the reactions, calculate the mass (in grams) of the product formed when 15.39 g of the underlined reactant completely reacts. Assume that there is more than enough of the other reactant 2K(s) + Cl_2(g) rightarrow 2KCl(s) 2K(s) + Br_2(l) rightarrow 2 KBr(s) 4 Cr(s) + 3O_2(g) rightarrow 2 Cr_2O_3(s) 2Sr(s) + O_2(g) rightarrow 2 SrO(s) For each of the acid-base reactions, calculate the mass (in grams) of each acid necessary to completely react with and neutralize 4.85 g of the base. HCl(aq) + NaOH(aq) rightarrow H_2O(l) + NaCl(aq) 2HNO_3(aq) + Ca(OH)_2 (aq) rightarrow 2H_2O(l) + Ca(NO_3)_2 (aq) H_2SO_4(aq) + 2KOH(aq) rightarrow 2H_2O(l) + K_2SO_4(aq)

Explanation / Answer

33 )

Ba + Cl2 ----------------------> BaCl2

137g                                        208 g

15.39g                                     ?

137 g Ba------------------------> 208 g BaCl2

15.39 g Ba ----------------------> 208 x 15.39 / 137 = 23.4 g

mass of product BaCl2 = 23.4 g

b)

CaO + CO2 --------------------->CaCO3

56 g                                          100 g

15.39 g                                        ??

CaCO3 mass = 100 x 15.39 / 56

                       = 27.5 g

c)

96 g O2 ----------------------> 152 g Cr2O3

15.39 g O2 -----------------> 24.4 g Cr2O3 product

d)

87.6 g Sr ------------------------> 104 g SrO

15.39 g Sr ---------------------> 18.3 g SrO product

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