For each of the reactions, calculate how many grams of the product form when 17.

Question

For each of the reactions, calculate how many grams of the product form when 17.8 g of the reactant in color completely reacts. Assume there is more than enough of the other reactant. Ca(s) + Cl_2(g) rightarrow CaCl_2(s) 2 K(s) + Br_2(l) rightarrow 2 KBr(s) 4 Cr(s) + 3O_2(g) rightarrow 2 Cr_2O_3(s) 2 Sr(s) + O_2(g) rightarrow 2 SrO(s) For the reaction shown, calculate how many grams of each product form when the given amount of each reactant completely reacts to form products. Assume there is more than

Explanation / Answer

a)
Ca + Cl2 ------------------> CaCl2

40 g                                  111 g

17.8 g                                 ?

40 g Ca --------------------> 111 g CaCl2

17.8 g Ca ---------------------> 17.8 x 111 / 40 = 49.4 g

mass of product = 49.4 g

b)

159.8 g Br2 --------------------> 238 g KBr

17.8 g Br2 ---------------------> 238 x 17.8 / 159.8 = 26.5 g

mass of product = 26.5 g

c)

96 g O2 -----------------------> 304 g Cr2O3

17.8 g O2 -------------------> ?

mass of product = 56.4 g

d)

175.2 g Sr -------------------> 207.2 g SrO

17.8 g Sr ---------------------> ?

mass of product = 21.0 g

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