What is the rise run and slope formed by the points and the activation energy fo

Question

What is the rise run and slope formed by the points and the activation energy for the reaction Print calculator Periodic Tabla uestion 24 at 30 If you were going to graphically determine the activation energy Consider this reaction data: of this reaction, What points would you plot? products Number T (K) k (s To avoid rounding point 1 0030769 95192 325 0.386 L errors, use at least I525 0602 three figures in all values. point 2: 0019048 .36817 Determine the rise, run, and slope of the line formed by these points. slope What is the activation energy of this reaction? J mol A Previous ® Give up s view salakon Check Answer Net Ext -L about us careers partners privacy policy terms of use contact us ha

Explanation / Answer

1. Given information in the question.
T(K) k(s-1)
325 0.386
525 0.892

2. In order to plot the given information in the graph, you must take the reciprocal of K and the Ln k. One of the reasons we do this is so that we obtain a straight line, so that we can find the slope.
T(K) k(s-1)
325 0.386
525 0.892
T(1/K) Ink
.003077 -0.952
.00190 - 0.114

3. Now find the slope. Slope is rise over run.
slope= rise/run
slope= change in In k / change in (1/K)
slope= (- 0.114--0.952)/(.00190 -.001177 )
slope= .838/ -.7.23*10^-4
slope=-1474.41
rise=.838
run= -7.23*10^-4

4. Find activation energy.
slope= -Ea/R
Ea=-(slope)(R)
Ea= - (-1474.41 K )(8.314 J/mol-K))
Ea= 12258.24 J/mol

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