A reactor engineer has one PFR that yields X 1 = 0.4. He needs to increase it to
ID: 489849 • Letter: A
Question
A reactor engineer has one PFR that yields X1 = 0.4. He needs to increase it to X2 = 0.8. He has an availiable a PFR and CSTR to attach in series. Both reactors can achieve the required conversion. Which combination is the most efficient? Calulate the reactor volume of the best combination if you have FA = 1 Kmol/s.
The reactor volume per unit molar molar flow of liming reactant (VR/FA) for PFR and CSTR is given by the following formulas:
PFR: VR/FA = 2 (XF - X1)2 + (XF - X1)/2
CSTR: VR/FA = 3 (XF - X1)2 + (XF - X1 )
Units are m3 s / kmol. XF and X1 are the output and input conversions of the reactor, respectively.
Explanation / Answer
Generally PFR is better when we dont have any reaction rate
so PFR followed PFR is best combination
sub xf = 0.8 and x1 = 0.4
PFR
Vr/Fa = 2 (0.8 -0.4)2 + (0.8 - 0.4)/2 =0.52
for xf = 0.4 and x1 = 0
also we will have same volume 0.52
CSTR
Vr/Fa = 3 (0.8 -0.4)2 + (0.8 - 0.4) =0.88
so volume required for PFR is less when compared to CSTR
hence PFR follwed by PFR is best combination and total volume will be 0.52 + 0.52 = 1.04 m3s/kmol.
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