Cells use the hydrolysis of adenosine triphosphate (ATP) to adenosine diphosphat

Question

Cells use the hydrolysis of adenosine triphosphate (ATP) to adenosine diphosphate (ADP) as a source of eneryg. Symbolically, this reaction can be represented as. ATP(aq)+H2O=ADP(aq)+H2PO4(aq) For this reaction deltaG0=-30.5KJ/mole.

1. Calculate K, the equilibrium constant at 25C

2. If all of the free enrgy from the metabolism of glucose goes into converting ADP back to ATP, how many moles of ATP can be produced for every mole of glucose? (Note: delta G0f for glucose is -911KJ/mole.) C6H12O6(s)+6O2(g)=6CO2+6H20.

Explanation / Answer

ATP(aq) + H2O ---------------> ADP(aq) + H2PO4(aq)    deltaG0 =-30.5KJ/mole.

delta Go = - RT ln K

- 30.5 = - 8.314 x 10^-3 x 298 x ln K

K = 2.22 x 10^5

equilibrium constant at 25C = 2.22 x 10^5

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