The compound below is identified as a(n)? carboxylic acid ketone aldehyde ester

Question

The compound below is identified as a(n)? carboxylic acid ketone aldehyde ester amine amide What is the IUPAC name of the compound shown? 3-hexanoic acid 2-ethyl pentanoate 2-ethylpentanoic acid 3-heptanoic acid 4-heptanoic acid Which ester would give CH_3CH_2CH_2COOH and CH_3CH_2OH upon hydrolysis? Which terms correctly describes the following reaction? Amines can be produced by? oxidation of amides reduction of amides methylation of amides esterification of amides amide cannot be converted in amines

Explanation / Answer

This has:

C=O; aldo COO,

so this must be an ESTER, since C=O and C-O-R is present!

Q21

for the molecule shown

C=O and C-OH is clearly carboxilic acid

longest chain of carbons --> 5 carbons, so pent

2nd carbon has ethyl branch

so

2-ethylpentanoic acid

is the correct answer

Q22

this is simply H2O + ESTER production

the left side:

3 carbons + C=O + C + C-OH

total carbons = 4+2 = 6

a can't be since C=OH wont exist

b, cant be sicne it has 5 carbons,

d can't be since ethyl (2carbons) is lost

so final answer is C

Q23

this reaction is going from ester to ketone

so

this must be dissociation, since we have two split cabrons

Q24

reduction of amides will get C=O to C-H , then only NH group will be present, which is typically an amine

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