Answer these questions in your lab notebook too may paste this paper into more b

Question

Answer these questions in your lab notebook too may paste this paper into more book you'd like). 1. In the development of the Claudius Chaperon equation, what was the principal assumption? 2. Consider the vaporization process you will be modeling in this lab: BR) AH & AS Predict whether the process will be endothermic or exothermic. Predict whether the system entropy would increase or decrease. Enthalpy of vaporization (Hanne): expected sign Entropy of vaporization (AS e): expected sign If the assumption in question MI is correct, and the signs for AH-w & AS follow your prediction in question U2, what would you expect the experimental data to look like if you plotted In (vapor pressure of B) versus 1/(absolute temperature) as predicted by the form of the Claudius- Chaperon equation (Eq. 6)? in water and heated in the experiment. But before you 4. A glass Erlenmeyer flask is introducing liquid into the flask there is some air already present. Imagine you the air-filled flask, then heated the gaseous contents by warming the water surrounding the flask. you think would happen to the air pressure in the mask as the temperature rises. The ideal gas law is shown below, with subscript A" for air. In the scenario described above, circle the variables in the ideal gas law that would be constant. 5. In the actual lab, you will introduce liquid B into the Erlenmeyer flask, and a mixture of air and vaporized liquid will be present. Which do you predict will change more rapidly with vapor pressure of B (Pa)? partial pressure of air (PA) What is your rationale? www Chekiang Department

Explanation / Answer

Q1.

For Clasius Clapeyron equation

we have this assumption as "main assuptions"

states, that the lines between Temperature and Pressure in equilibrium between two phases, can be modeled via astriaght line

This is due to the fact that:

dGphase 1 = dGphase 2

let phase 1 = liquid and phase 2 = gas

so

dGliquid = dGgas

dG = dH - T*dS

so

dH1 - T*dS1 = dH2-T*dS2

so

dH1-dH2 = T(dS1-dS2)

eventually

we assume that

dS = entorpy change ni phases

dh = entropy change in phases

Until we end up:

ln(P2/P1) =- Hvap/R*(1/T2-1/T2)

we related T vs. P

actually

ln(P) vs 1/T and slope =- dHvap/R

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