secure l https //session masteringchemistry.com/myct/temview?assignmentProblemlo

Question

secure l https //session masteringchemistry.com/myct/temview?assignmentProblemlo 78787595 Chem 3ASP20 17TuAMLab Part A Exercise 8 65 Determine the limitng reactant for the reaction. Lead ions can bepreciptated from solution with Naci Express your answer as an ion. according to the following When 135 8 g of NaCI are added to a solution containing 1957 gof Pb a PbCl precipitate forms. The precipitate is fitered and dried and found to have a mass of 2500g Submit My Answers Gere Part B Determine the theoretical yield of PbCl2 for the reaction Express your answer using four significant fig Submit My Answers Grye Ug Part C Determine the percent yield for the reaction. Express your answer using four significant figures. percent yield Submit My Answers

Explanation / Answer

A)

limiting reactant:

mol of Pb+2 ions = mass/MW = 195.7/207.2000 = 0.94449

mol of NaCl = mass/MW = 135.8/58.8 = 2.3095

ratio is 1:2

so

0.94449 mol of Pb require --> 2*0.94449 = 1.88898 mol of NaCl, which we DO have

so Pb+2 limits reaction

B)

theoretical yield:

0.94449 mol of Pb+2 -- > 0.94449 mol of PBcl2

mass = mol*MW = 0.94449 *278.1 = 262.662669 g of PbCl2

C)

% yield = real /theoretical * 100% = 250/262.662669*100

= 95.179 %

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.