The rate constant of a chemical reaction increased from 0.100 s 1 to 3.20 s 1 up

Question

The rate constant of a chemical reaction increased from 0.100 s 1 to 3.20 s 1 upon raising the temperature from 25.0 GC to 45.0 oC Part A where T is the initial temperature and T2 is the final temperature. Calculate the value of Express your answer numerically K-1 T2 T Submit Hints My Answers Give Up Review Part Part B where ki and k2 correspond to the rate constants at the initial and the final temperatures as defined in part A Calculate the value o Express your answer numerically lae). Submit Hints My Answers Give Up Review Part

Explanation / Answer

A) Given T1 = 25 C = 298 K and T2 = 40 C = 318 K

Thus the vlaue of (1/T1 - 1/T2 ) = 1/298 -1/318

= 2.11x10-4

B) Given k1 = 0.1/s and k2 =3.2/s

Thus ln k2/k1 = ln 3.2/0.1

= 3.465

C) T0 calculate Ea of reaction use Arrhenius equation

ln (k2/k1) = Ea/R [1/T1 -1/T2]

substituting the values fro previous calculations

3.465 = [Ea /8.314J ] x2.11x10-4

Thus Ea =13.655x 104 J

= 136.55 kJ/mol

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