The rate constant of a chemical reaction increased from 0.100 s ? 1 to 3.00 s ?
ID: 787822 • Letter: T
Question
The rate constant of a chemical reaction increased from 0.100 s?1 to 3.00s?1 upon raising the temperature from 25.0 ?C to 49.0?C . Part A Calculate the value of (1T2?1T1) where T1 is the initial temperature and T2 is the final temperature. The rate constant of a chemical reaction increased from 0.100 s?1 to 3.00s?1 upon raising the temperature from 25.0 ?C to 49.0?C . The rate constant of a chemical reaction increased from 0.100 s?1 to 3.00s?1 upon raising the temperature from 25.0 ?C to 49.0?C . Part A Calculate the value of (1T2?1T1) where T1 is the initial temperature and T2 is the final temperature. Part A Calculate the value of (1T2?1T1) where T1 is the initial temperature and T2 is the final temperature.Explanation / Answer
(1/T2?1/T1) = (1/(49+273)) - (1/(25+273)) = - 2.5*10^-4
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