Given a gas-phase reaction H 2 (g) + I 2 (g) 2 HI(g). The equilibrium constant o

Question

Given a gas-phase reaction H2(g) + I2(g) 2 HI(g). The equilibrium constant of this reaction Kp = 0.654. At a certain moment of the reaction run, the partial pressures of gases in the reaction mixture are 0.127 atm for H2, 0.134 atm for I2, and 0.0550 atm for HI. Calculate the Qp and answer the following questions.

The value of Qp is . _________(Fill in the blank; show the proper number of significant figures; do not use scientific notation.)

Is the reaction at equilibrium?  (Fill in the blank indicating Yes or No only.)

If your answer to the above question is Yes, skip this question. If your answer is No, then in which direction does the reaction proceed?   (Fill in the blank indicating Left to right or Right to left only.)

Explanation / Answer

H2(g) + I2(g) 2 HI(g)

Kp = 0.654

Qp   = [HI]2/[H2][I2]

         = (0.055)^2/0.127*0.134

        = 0.178 >>>> 3 significant figures

Kp>Qp the equilibrium shift to right side.

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