What is the freezing point of an aqueous 2.08 m NaCl solution? (K _fp for water

Question

What is the freezing point of an aqueous 2.08 m NaCl solution? (K _fp for water is 1.858 degree C/m) What is the freezing point of a 0.27 m solution of glucose, C _6H _12O _6. in water? (K _fp for water is 1.858 degree C/m.) What is the freezing point of a solution containing 2.80 grams benzene (molar mass = 78.11 g/mol) dissolved in 43.0 grams paradichlorobenzene (molar mass = 147.0 g/mol)? The freezing point of pure paradichlorobenzene is 53.0 degree C and the freezing point depression constant, K _fp is -7.10 degree C/m. A solution consisting of 0.21 mol of methylbenzene, C _6H _5CH _3, in 259 g of nitrobenzene, C _6H _5NO _2, freezes at 0.3 degree C. Pure nitrobenzene freezes at 6.0 degree C. What is the freezing-point depression constant of nitrobenzene? A 2.5-g sample of a small protein having a molecular weight of 72,000 g/mol is dissolved in 32.0 mL of water at 25 degree C. What is the osmotic pressure of the solution? (R = 0.0821 L middot atm/K middot mol; 1 atm = 760 mmHg)

Explanation / Answer

11)

11)
NaCl breaks into 2 particles
so, i=2

Tf = i*Kf*M
= 2*1.858*2.08
= 7.73 oC

This is depression in freezing point
freezing point of pure water 0 oC

Freezing point is - 7.73 oC

Answer: - 7.73 oC

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