Click on the Reset\' button on the tower right hand side. then select None for t
ID: 494288 • Letter: C
Question
Click on the Reset' button on the tower right hand side. then select None for the Constant Parameter Add 75 heavy species particles using the 'Gas m chamber' box the temperature should read 300 K. If it does not. use the 'heat control' box to adjust the temperature What happens to the temperature and pressure when you use 'scuba diver Dan' to decrease the size of the box? Click on the 'Reset' button, then set the gas in the chamber to be 50 heavy species and 50 light species Cool the chamber to Absolute zero (O Kelvin). What happens to the pressure? Describe the particles. Are the particles completely at rest? Use "Dan" to compress the chamber as much as possible white cooling with ice to absolute zero. Have -Dan- quickly expand the chamber to its maximum volume Observe what occurs a Which species of molecule reaches "Dan" first? Why does this specks arrive first? Briefly explain and provide the equation we covered in class to support your answer.Explanation / Answer
2) As per the ideal gas law:
PV = nRT
As the size of the box is decreased, volume gets lowered as a result collision between particles increases which increases the kinetic energy, thereby increasing the temperature. Also, as the volume decreases, the particles will strike the walls of the box faster, increasing the force exerted per unit area which is nothing but the pressure.
Hence, temperature and pressure will increase.
4) a)At absolute zero, T = 0 K, hence as per the ideal gas equation, pressure will be zero.
b) The particles will move with very low energy, however they cannot be completely at rest. At such low temperatures one needs to treat the partcle as a quantum mechanical system where heisenberg's uncertainity principle must be accounted for.
i,e (position uncertanity)*(velocity uncertainity) > h/2pi
where h is the plancks constant
If the velocity were zero, i.e if the particle was completely at rest, this would imply that position is zero which would violate the uncertainity principle. Hence, the particles would still be moving, although at a very very low energy.
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