Consider the following experiment: In a 1 liter box we have Gas A, with a pressu

Question

Consider the following experiment: In a 1 liter box we have Gas A, with a pressure of 300 torr. It is connected to another liter box containing 300 torr of Gas B. A valve prevents the gases from mixing. When the valve is opened, the gases mix, Now each box contains Gas A and Gas B. The pressure in the whole system is 300 torr. In System 1, does the box containing Gas A contain the same number of particles as the box holding Gas B? Explain why. In system 2, does the first box contain the same number of particles as the second box? What is the total volume of system 2 (et the volume of the connecting tube be negligible.)

Explanation / Answer

Q14

a)

Gas A should have exactly the same amount of molecules than that of B, since it is due to avogrados law:

V1/n1 = V2/n2, whenever T and P are both constant ( which is the case)

Q2.

Correct, since A+ B mix will eventually add up the same number of moles due to the ratio

P1V1/(n1*T1) = P2V2/(n2*T2)

T1 = T2 and P1 = P2 so

n1 = n2

Q3.

Total V = V1+V2 = 300 + 300 = 600 L

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