Write the overall chemical reaction, the detailed ionic equation, and the net io

Question

Write the overall chemical reaction, the detailed ionic equation, and the net ionic equation, for the following acid-base reactions: acetic acid and potassium hydroxide hydrocyanic acid and ammonia nitric acid and sodium hydroxide sulfuric acid and ammonia (1:1 mole ratio) carbonic acid and sodium hydroxide (1:2 mole ratio) Write equations for, and classify, the following reactions: nitric acid and cobalt (II) carbonate sodium sulfate and barium nitrate ammonia and acetic acid hydrochloric acid and calcium carbonate c. sodium hydroxide and nickel carbonate lead acetate and hydrochloric acid iron (III) nitrate and sodium hydroxide If 5.00 grams of sodium hydroxide is dissolved to make 600 mL of solution, what is its molarity? How much potassium chloride has to be dissolved in water to produce 2.0 liters of a 2.45 M solution? If 24.63 grams of magnesium chloride is dissolved to make exactly 3 liters of solution calculate the concentrations of the ions in the solution (in moles/liter). What is the molarity of the solution that results from adding 25 mL of a 0.15 M solution of sodium hydroxide to sufficient water to make 500 mL of solution? What volume of a 2.50 M solution of hydrochloric acid is required to prepare 2.0 liters of a 0.30 M solution? When excess silver nitrate was added to a 25.0 mL sample of a solution of calcium chloride, 0.9256 gram of silver chloride precipitated. What is the concentration of the calcium chloride solution? What volume of a 0.291 M solution of NaOH is required to reach the equivalence point in a titration against 25.0 mL of a 0.350 M HCI? KHP (potassium hydrogen phthalate KHC_3H_4O_4) is often used as a primary standard for sodium hydroxide standardization: HC_3H_4O_4^-(aq) + OH^-(aq) rightarrow C_3H_4O_4^2-(aq) + H_2O(l)

Explanation / Answer

Question 7 a

Molarity of NaOH = 5 x 1000 /40 x 600 = 0.2083 M

Question 7 b

Mass of KCl = 2.45 x 2 x 74.5513 = 365.295 gm of KCl is need

Question 7c

Molar mass of MgCl : 95.211 g/mol

Molarity of MgCl = 24.63 / 95.211 x 3 = 0.08622 M

Question 8a

Molarity of the solution = 25 x 0.15 / 500 = 0.0075 M

Quesiton 8b

Volume of HCl = 2 x 0.3 / 2.5 = 0.24 Liter or 240 ml

Hence we need 240 ml of 2.5 M HCl solution to make 2 L of 0.3 M solution.

Quesiton 9

Moles of Silver Chloride (Molar mass: 143.32 g/mol) = 0.9256 / 143.32 = 0.006458 M

Concentration of CaCl2 = 0.006458 x 1000 / 25 = 0.2583 M

Question 10

Volume of NaOH = 25 x 0.35 / 0.291 = 30.07 ml

Hence we need 30.07 ml of NaOH is needed to neutralize the 25 ml of 0.35 M HCl

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.