Elemental mercury can be produced from its oxide: 2HgO( s )2Hg( l )+O2( g ) Use

Question

Elemental mercury can be produced from its oxide:
2HgO(s)2Hg(l)+O2(g)

Use data in Appendix B to calculate Ssys for this reaction.

Use data in Appendix B to calculate Ssurr for this reaction.

Use data in Appendix B to calculate Stotal for this reaction.

Is the reaction spontaneous under standard - state conditions at 25C?

Substance and State Aluminum All) Barium Beryli Bels Baron Bromine Br (ag) Br: CdS (s) AH AG mol 330.0 704.2 180.0 537,6 855.0 8.0 1213,0 473.2 -1362.2 -609, H 902.5 8150 1136.0 9.4 4038 388,7 36.1 876 1273,5 1094.3 968.9 121,5 30.9 30.3 75.9 391,5 3139 258,4 -933.3 28.3 50,9 62.5 170.1 2,1 132.2 9.5 13,8 5.9 254.3 54.0 90.0 1749 R24 152.2 67.6 115.3 54 64.9 23 Substance and State Calcium CaF2ts) C graphite) C diamond CO, (ag) CO, (ag) HOU, (af) HCN) COCI2lg) CsF(s) CsBr(s) AH" 59.8 11208 7167 0.5 1138 08.9 89.0 6.7 72 AG (kl/mol) 75.6 748.8 12.5 603.3 1129.1. 2.9 137.2 394.4 5868 25.0 64.6 204.9 49.6 292.0 525.5 114.5 340.6 05.3 Kamal 68,5 83.4 24 97.6 7.6 874, 2.8 151.3 237.7 283,4 85.2 75.6 92.8

Explanation / Answer

Ssys   = ( 2 x 76.02 + 205.0 ) - 2 x 70.29

              = 216 .5 J / k

H = (0 + 0) - (2 x –90.83) = 181.7 kJ / mol K

T = 25 + 273 = 298 K

Ssurr = - 181.7 x 10^3 / 298

           = - 610 J / K

Stotal = Ssys + Ssurr

              = 216.5 - 610

             = -393 J/ K

Stotal is negative so it is not spontaneou at 25oC

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