An Open Tubular column with a diameter of 197 micrometers and a stationary phase

Question

An Open Tubular column with a diameter of 197 micrometers and a stationary phase thickness on the inner wall of 0.64 micrometers passes unretained solute through in 65 s. A particular solute has a retention time of 437 s.

What is the partition coefficient for the solute?

K =

An open tubular column with a diameter of 197 Arm and a stationary phase thickness on the inner wall of 0.64 Am passes unretained solute through in 65 s. A particular solute has a retention time of 437 s. (b) What fraction of time does this solute (a) What is the partition coefficient for this solute? spend in the stationary phase? Number Number K- 559.43 5 0.85 otal

Explanation / Answer

b)

k' = t'R / tM = (tR-tM) / tM = (437 sec– 65 sec) / 65 sec = 5.72307

k' = ts / tm => ts = k' * tm = 5.72 x 65 sec = 371.8 sec
fraction in stat. phase = 371.8/437 = 0.850

a)

K = Cs / Cm

k' = K Vs/Vm

=> K = k' * Vm / Vst = k' * (L*Amob)/(L*Ast) = k' Amob / Ast

Ast = Atotal - Amob = pD2/4 - pDmob2/4
= p/4 [(437 x10-6 m)2 – (431.28 x 10-6 m)2]
= 3.90 x10-9 m2

K = k' * Amob / Ast = 5.72* 65 x10-7 m2/ 3.90 x10-9 m2
= 9533

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.