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For liquid acetone at 25 degree C and 1 bar: beta = 1.637 times 10^-3 degree C^-

ID: 500623 • Letter: F

Question

For liquid acetone at 25 degree C and 1 bar: beta = 1.637 times 10^-3 degree C^-1 k = 64 times 10^-6 bar^-1 V = 1.325 cm^3 g^-1 Find the change in volume in cm^3 g^-1 for a change from 25 degree C and 1 bar to 0 degree C and 6 bar. Calculate the molar volume in cm^3 g^-1 of saturated vapor by the Redlich/K wong equation for Propane at 70 degree P^sat = 23.75 bad compare the results with values found by the 2^nd virial generalized correlation method. Calculate the heat required in kJ to raise the temperature of 1 mole of Nitrogen at 1 atm from 20 degree C to 500 degree C. Nitrogen can be assumed as an ideal gas. One mole of an ideal gas at 150 degree C and 6 bar with C_p = (7/2) * R and C_v = (5/2) * R undergoes the following mechanically reversible process: Step 12: Expands adiabatically to a pressure of 2 bar Step 23: Heated at constant volume to its initial temperature Step 31: Returns to its initial state isothermally Calculate W, Q, Delta U and Delta H for steps a, b, c and total. Put your answers in Joules in a table as shown below (draw table in your exam booklet!).

Explanation / Answer

3. Heat required to increase certain temperature of a substance is given by Heat=nCPdT n=number of moles of gas, CP=specific heat at constant pressure and dT temperature change.

Purtting the values we get Heat required= 1*1.4R*(573-293)=1.4*8.314*480 kJ=5.587 kJ