How many molecules of butanol are in 124 grams of butanol (C_4 H_10 O)? Give the

Question

How many molecules of butanol are in 124 grams of butanol (C_4 H_10 O)? Give the formula for: cupric bicarbonate___________ ferric oxide___________ Calcium chloride ___________ aluminum sulfate ___________ Magnesium nitride ___________ ammonium carbonate ___________ Give the IUPAC (systematic) name for the following, use roman numerals where needed: Fel_2___________ N_2 O ___________ K_2 O ___________ Fe_3 P_2 ___________ Be(NO_2)_2 ___________ Br_2 O_7 Give the oxidation number of the underlined element The carbon in the carbonate ion NO_3^-1 PO_3^-3 ___________ ___________ ___________

Explanation / Answer

5) Butanol molecular mass= 74.12 g

Number of moles (n)= 124/74

= 1.675 moles of butanol in 124g

To calculate the number of molecules multiply by Avogadro's number(6.023x10^23)

= 1.67x 6.023x10^23

= 1.005x10^24 molecules of butanol

6) cupric bicarbonate- Cu (HCo3)2

Ferric oxide- Fe2O3

Calcium chloride- CaCl2

Aluminum sulphate- Al2(So4)3

Magnesium nitride- Mg3N2

Ammonium carbonate- (NH4)2 CO3

7) FeI2 IUPAC name is Iron (II) iodide

N2O IUPAC name is dinitrogen monoxide

K2O - potassium oxide

Fe3P2 - Iron (III) phoshide

Be(NO2)2 - berilium nitrite

Br2O7- dibromine heptoxide

8) a) The oxidation number of carbon is +4

Carbonate ion ( CO3)2-

So oxidation state of oxygen is -2

O2= -6

Total charge = +4-6 =-2

So the oxidation carbon is +4.

B)No3

Charge -1 overall oxidation number of the ion is -1

3 oxygens =-6 oxidation number

So N oxidation number is -6+1 =5

C) po3

The oxidation state of oxygen is -2

Let the oxidation state of p be x.

The net charge on the ion is -3

X+3(-2) =-3

X-6 =-3

X=+3

So the oxidation number of p is +3.

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.