(IV) Answer the questions based on the following: a) K_2Cr_2O_7 rightarrow Cr_2O
ID: 505430 • Letter: #
Question
(IV) Answer the questions based on the following: a) K_2Cr_2O_7 rightarrow Cr_2O_3 (s) What is the oxidation # of Cr in K_2Cr_2O_7? __ What is the oxidation # of Cr in Cr_2O_3 ___ ls Manganese an oxidizing agent or reducing agent ? b) H_2O_2 (aq) rightarrow O_2 (g) What is the oxidation # of oxygen in H_2O_2? ___ What is the oxidation of oxygen # O_2 ? __ ls oxygen an oxidizing agent or a reducing agent ? __ (v) The combustion of methane is shown in the following equation: CH_4(g) + 2O_2(g) rightarrow CO_2(g) + 2H_2O (l) If 17.0 mol of CH_4 are reacted with excess amount of O_2, what is the volume of CO_2 in liters produced at 25.0^degree C and 0.980 atm ? (VI) A sample of NH_3 gas is completely decomposed to nitrogen and hydrogen gases. a) Write a balanced chemical equation of this reaction.Explanation / Answer
(IV)
(a)
Oxidation # of Cr in K2Cr2O7 is: +6
Oxidation # of Cr in Cr2O3 is: +3
Manganese is an oxidizing agent, as is visible from the strong oxidizing agent KMnO4
(b)
Oxidation # of O in H2O2 is: -1
Oxidation # of Cr in O2 is: 0
Oxygen is an oxidizing agent.
(V)
17 moles methane would produce 17 moles O2, which occupies 22.4*17 L volume at STP
Using relation:
P1V1/T1 = P2V2/T2
Putting values:
1*(22.4*17)/273 = 0.98*V2/298
V2 = 424.15 L
(VI)
Decomposition reaction is:
2NH3 ----> N2 + 3H2
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