General Chemistry I Laboratory Experiment No. 9 he Molecular weight Data Sheet T
ID: 506190 • Letter: G
Question
General Chemistry I Laboratory Experiment No. 9 he Molecular weight Data Sheet Trial Trial 3. Unknown Liquid Number: Trial 2 ional Trial 1 Same as Same as Same as Trial 1 Trial 1 Mass of empty nask, stopper, tube, cork 101 ,265 Trial 1 (to 0.001 g) 26 three lo determinations to check for balance consisten Average Mass Mass of cork ring, empty flask, stopper, tube, cork 2 9. to 0.01 52 Temperature of Boiling Water Surrounding flask Atmospheric Pressure Mass of condensed vapor, loi, 1619 lo flask, stopper, tube, cork (to 0.001 g) (At least three times) Average Mass Determination of System Volume Auera Mass of cork ring, flask, H21 20 S stopper, tube, cork and water 43g, 6 (to 0.01g) Temperature of Water in 120 C Flask Literature Density of Water 999 75 atExplanation / Answer
Mass of condensed vapor in trial 1 = 101.77-101.26 = 0.51 gm
Mass of condensed vapor in trial 2 = 101.76- 101.26 =0.50 gm
Mass of water in the flask = 421.76-134.56 = 287.2 gm
Volume of water in the flask = 287.2 mL (as density of water = 1gm//mL)
= 0.2872 L
Temperature in trial 1 : 100oC , 373 K
Temp in trial 2 : 99oC 372 K
Atmosperic pressure in Trial 1 (torr) = 760 torr = 1atm
Atmosperic pressure in trial 2 = 760 torr =1atm
For trial 1 :
PV = nRT
or, n = PV/RT
= 1 atm *0.2872L / 0.082L atm/K/mol * 373 K = 9.39*10^-3 mol
Molar mass = mass of condensed liquied / moles /
= 0.51 gm /9.39*10^-3 mol
= 54.3 gm/mol
-------------------------------------
Trial 2 :
PV = nRT
or, n = PV/RT
= 1 atm *0.2872L / 0.082L atm/K/mol * 373 K = 9.39*10^-3 mol
Molar mass = mass of condensed liquied / moles /
= 0.51 gm /9.39*10^-3 mol
= 54.3 gm/mol
-------------------------------------
Trial 2 :
PV = nRT
or, n = PV/RT
= 1 atm *0.2872L / 0.082L atm/K/mol * 373 K = 9.39*10^-3 mol
Molar mass = mass of condensed liquied / moles /
= 0.51 gm /9.39*10^-3 mol
= 54.3 gm/mol
-------------------------------------
Trial 2 :
PV = nRT
or, n = PV/RT
= 1 atm *0.2872L / 0.082L atm/K/mol * 372 K = 9.42*10^-3 mol
Molar mass = mass of condensed liquied / moles /
= 0.50 gm /9.42*10^-3 mol
= 53.08 gm/mol
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