Lab11 Report Name 2. Say that 150 with a mass of 151 grams is added to mL of a s
ID: 506891 • Letter: L
Question
Lab11 Report Name 2. Say that 150 with a mass of 151 grams is added to mL of a solution with a mass of 252 grams in a coffee cup calorimeter Before the mixing the temperature of each solution was 22.00 °C. After the reaction was complete, the is temperature of the mixed solutions was 30.00 C. The specific heat the mixed solutions essentially the same as water's, 4.184 J/g °C. a. Calculate the amount of heat generated by this reaction. b. How many moles of HCl were added to the calorimeter? c. How many moles of NaOH were added to the calorimeter? d. What is the balanced chemical equation for this reaction? e. So, what is the limiting reagent in this reaction and how many moles of it actually reacted? f. Now, what is the excess reagent in this reaction and how many moles ofit actually reacted? g. What is the value of AH,,n? h. What is the balanced thermochemical equation for this reaction based on this data? i. Finally, calculate the AH using AHrvalues and calculate the percent error for this experiment. Prlab questions continue on the next page!Explanation / Answer
Given
NaOH
150 ml of 1.5 M NaOH
Volume = 150 ml = 0.15 L
Molarity = 1.5 M (mol/L)
mass m1 = 151 g
250 ml of 1 M HCl
Volume = 250 ml = 0.25 L
Molarity = 1 M
mass m2 = 252 g
total mass of solution m = 151 + 252 = 403 g
Initial temperature T1 = 22 C
Final temperture T2 = 30 C
Cp = 4.184 J/g.C
q = m * Cp * (T2 - T1) = 403 * 4.184 * (30 - 22 ) = 13489.22 J = 13.489 KJ answer (a)
No. of moles of HCl = Volume * Molarity = 0.250 L * 1 mol/L = 0.25 moles answer (b)
No. of moles of NaOH = Volume * Molarity = 0.15 L* 1.5 mol/L = 0.225 moles answer (c)
NaOH (aq) + HCl (aq) -----> H2O (l) + NaCl (aq) answer (d)
limiting reagent is NaOH answer (e)
as 0.25 moles of HCl requires 0.25 moles of NaOH but only0.225 moles of NaOH are there so NaOH is limiting
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.