Titration lab: Indicate if the calculated NaOH molarity will be higher, lower, o

Question

Titration lab:
Indicate if the calculated NaOH molarity will be higher, lower, or the same as the actual molarity in each of the following situations. a. An air bubble left the tip of your buret during the titration. b. When dispensing some KHP into an Erlenmeyee flask, you didn't see that a small portion of it fell outside the flask. c. After you reached the endpoint, you forgot to rinse the drop off the tip of your. Urey into the Erlenmeyer flask. d. There were some water droplets inside the Erlenmeyer flask to which you added your KHP. Titration lab:
Indicate if the calculated NaOH molarity will be higher, lower, or the same as the actual molarity in each of the following situations. a. An air bubble left the tip of your buret during the titration. b. When dispensing some KHP into an Erlenmeyee flask, you didn't see that a small portion of it fell outside the flask. c. After you reached the endpoint, you forgot to rinse the drop off the tip of your. Urey into the Erlenmeyer flask. d. There were some water droplets inside the Erlenmeyer flask to which you added your KHP.
Indicate if the calculated NaOH molarity will be higher, lower, or the same as the actual molarity in each of the following situations. a. An air bubble left the tip of your buret during the titration. b. When dispensing some KHP into an Erlenmeyee flask, you didn't see that a small portion of it fell outside the flask. c. After you reached the endpoint, you forgot to rinse the drop off the tip of your. Urey into the Erlenmeyer flask. d. There were some water droplets inside the Erlenmeyer flask to which you added your KHP.

Explanation / Answer

1) Air bubble will occupy some extra volume and the measured volume will be higher. This in turn increases the calculated molarity than the actual.

2) Calculated molarity will be higher than actual value. Since the no of moles is decreasing and the solution will take a higher volume. When this volume is introduced along with the mistaken concentration of KHP, the concentration increases.

3)This don't have much effect on the calculated molarity and it will be almost same.

4) If the concentration of water droplet is significantly large, it will reduce the concentration of KHP and more volume will be need to neutralize the NaOH solution. Therefore the calculated molarity will be higher than actual molarity. If the concentration of water droplets are very less then it don't have much effect on the calculated molarity

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