1. How many conversion factors (relationships) are given in the following chemic

Question

1. How many conversion factors (relationships) are given in the following chemical equation? 2 NO(g) + 5 H2(g) 2 NH3(g) + 2 H2O(g)

2 conversion factors

4 conversion factors

5 conversion factors

6 conversion factors

2. Consider the following reaction: 2 NO(g) + 5 H2(g) 2 NH3(g) + 2 H2O(g) Which set of solution maps would be needed to calculate the maximum amount of ammonia (NH3), in grams, that can be synthesized from 45.8 g of nitrogen monoxide (NO) and 12.4 g of hydrogen (H2)? I. g NO mol NO mol NH3 g NH3 II. g H2 mol H2 mol NH3 g NH3 III. g NO mol NO mol H2O g H2O IV. g H2 mol H2 mol H2O g H2O.

solutions maps I and II solutions maps I and V solutions maps I and III solutions maps II and III

Explanation / Answer

Question 1.

The reaction:

2 NO(g) + 5 H2(g) 2 NH3(g) + 2 H2O(g)

if there are 4 species, then we can relate as follow: (remember that we cant repeat ratios)

That is,

5 H2 = 2NH3; is the same as 5/2H2 = NH3 or H2 = 2/5*NH3

then, knowing this

For NO:

NO = H2; NH3, H2O (3x)

meaning that we can relate NO to all other 3

Then, choose H2,

H2 = NH3, H2O (2x)

Note that we cant repeat NO, so only 2 x

Finally; only left:

NH3 = H2O ( 1x)

total ratios = 3+2+1 = 6

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