Use the References to access important values if needed for this question. For t

Question

Use the References to access important values if needed for this question. For the gas phase decomposition of ethyl acetate, CH3CooC2H5---- CH3CooH C2H4 the rate constant has been determined at several temperatures. When ln k in s 1 is plotted against the reciprocal of the Kelvin temperature, the resulting linear plot has a slope of -2.41x104 K and a y-intercept of 28.8 The activation energy for the gas phase decomposition of ethyl acetate is kJ/mol Retry Entire Group 8 more group attempts remaining Submit Answer

Explanation / Answer

Solution:-

Arrhenius equation is...

k = A e-Ea/RT

taking ln to both sides...

ln k = - (Ea/R)*1/T + ln A

straight line equation is y = mx + c

in this equation m is the slop and c is the intercept.

if we compare our equation with straight line equation then..

then slop = - Ea/R and intercept = ln A

if a graph is plotted ln k vs 1/T where time is in kelvin then slop = -Ea/R and intercept = ln A.

From the given information, slop is -2.41 x 104 K that means,

-Ea/R = -2.41 x 104 K

and,

ln A = 28.8

we are asked to find out the activation energy. so,....

-Ea/R = -2.41 x 104 K

we have negative sign on both sides so it is canceled out and on cross multiply..

Ea = R(2.41 x 104 K)

value of R is 8.314 x 10-3 kJ/(mol* K)

On plugging in the value of R..

Ea = 8.314 x 10-3 kJ/(mol* K)(2.41 x 104 K)

Ea = 200.4 kJ/mol

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