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Hydrogen gas and nitrogen gas react to form ammonia according to the reaction. 3

ID: 510015 • Letter: H

Question

Hydrogen gas and nitrogen gas react to form ammonia according to the reaction. 3 H_2 + N_2 rightarrow 2NH If 4.0 moles H_2 with 2.0 mol of N_2 are reacted. The limiting reactant is: a. N_2 b. Can't be decided c. NH_3 d. H_2 The reduction half reaction: a. 2H + 2e rightarrow H_2 b. Cu rightarrow Cu^2+ + 2e^- c. Ci^2+ rightarrow Ci + 2E^- d. 2H_2O + 2e rightarrow H_0O + 2OH^- Which of the following substances would dissolve in water: z. Zn(NO_3)_2 b. AgCl c. CaSO_4 d. BaSO_4 Which of the answers below is an ionic representation for the reaction between Calcium nitrate and sodium sulfide solutions to form solid calcium sulfide and sodium nitrate solution. a. Ca^2+(aq) + NO^-_3(aq) + Na^+(aq) + S^2- (aq) CaS(s) + NaNO_3(s) b. Ca^2+(aq) + NO^-_3(aq) + Na^+ (aq) + S^2-(aq) CaS(s) + Na^+ (aq) + NO^-_3(aq) c. Ca^2+ (aq) + 2NO^-_3(aq) + Na^+(aq) + S^2-(aq) CaS(s) + Na^+ (aq) + NO^-_3 (aq) d. Ca^2+(Aq) + 2NO^-_3 (aq) + 2Na^+ (Aq) + 2S^2-(aq) CaS(s) + 2Na^+ (a

Explanation / Answer

Answer 11:

A limiting reactant is a species which is present in limiting amount for a complete reaction or complete reactants to product conversion to occur. Here, 3 moles of hydrogen and one mole of nitrigen needs to be there i.e. 3:1 ratio of hydrogen to nitrogen for 2 moles of ammonia preparation.

Given: 4 moles of hydrogen and 2 moles of nitrogen i.e. 2:1 ratio of hydrogen to nitrogen. The above ratio is lesser than 3:1 ratio for complete reaction. Therefore, hydrogen is a limiting reactant. i.e. option (d)

Note: If two additional moles will be there, then total 6 moles of hydrogen with 2 moles of nitrogen will result in 3:1 ratio, and so complete reactant to product formation will occur.

Answer 12:

A reduction is a process where electrons gets absobed by the chemical species, resulting in reduction of positive charge on chemical species. Here,

Answer 13.

Note: All are inorganic compounds, so in principle, should be water soluble but:

Answer 14:

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