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help with #6-#8 NT24 in the data the results of the abrwe r in the IKrvasing act

ID: 510861 • Letter: H

Question


help with #6-#8

NT24 in the data the results of the abrwe r in the IKrvasing activity. the data for binasors How does this value oompare with your the Eo value the ou cu 2 half reaktion given r Table 241 and ae mi value for tion calculate the value iarthw half cell celloombinat in the s used e eo value for the Cu/cu 2 half reaction gi value for cel combination I lo calculate the Eo value the snlsa 2 hali volts Use the for 5 and 6 to predict potent al for delambrauen 4. values the volts value 47 Hon does this value compare with your es &

Explanation / Answer

6)

Sn/Sn2+ || Cu/Cu2+

Sn2+ + 2e- <-----> Sn(s)

Cu2+ + 2e- <------> Cu(s) Eo = 0.337V

Sn(s) + Cu2+ <-----> Sn2+ + Cu

Copper is reduced by Sn

Ecell = Ered - Eoxd

0.579 = 0.337 - EOx

-EOx = 0.579 - 0.337

ESn/Sn2+= - 0.242 V

7)

Value of Zn/Zn2+ from cell combination 3 is

Zn/Zn2+|| Cu/Cu2+

Ecell = ECu/Cu2+- EZn/Zn2+

Ecell = 0.337 - EZn/Zn2+

-EZn/Zn2+ = 1.236 - 0.337

EZn/Zn2+ = -0.889 V

Using the values Ecell of cell combination of 4 is

Sn/Sn2+ || Zn/Zn2+

Ecell = EZn/Zn2+ - ESn/Sn2+

Ecell = -0.889 - (-0.242)

Ecell =-0.657 V