You decide to pan for gold. You find a shimmery piece of gold colored material i

Question

You decide to pan for gold. You find a shimmery piece of gold colored material in your pan. You know the area is also known for having "fool's gold" or pyrite. Pyrite is the mineral FeS_2. You deleted the best way to determine if you have gold or pyrite is to perform a calorimetry experiment. You look up the specific heat of gold (0.129 J/g degree C) and of pyrite (0.520 J/g degree C). You then collect the following data: Mass of sample 5.300 g Initial temperature of sample 98.20 degree C Mass of water 100.00 g Initial temperature of water 22.30 degree C Final temperature of water and sample 22.80 degree C What metal do you have? Justify your answer by showing your work and calculating the specific heat of the metal.

Explanation / Answer

Solution:- mass of sample = 5.300 g

initial temperature of sample = 98.20 degree C

mass of water = 100.00 g

initial temperature of water = 22.30 degree C

final temperature of water and sample = 22.80 degree C

delta T for sample = 22.80 - 98.20 = -75.4 degree C

delta T for water = 22.80 - 22.30 = 0.50 degree C

q = m c delta T

where q is the heat energy, m is mass, c is specific heat and delta T is change in temperature.

we know that, heat given = - heat taken

let's make the set up and calculate the specific heat, c for the unknown metal.

5.300 g x c x (-75.4 0C) = - [100.00 g x 4.184 J/(g*0C) x 0.50 0C]

-399.62c g*0C = - 209.2 J

c = 209.2 J/(399.62c g*0C)

c = 0.523 J/g*0C

calculated value is closer to the given specific heat of pyrite. So, the metal we have is Pyrite.

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