(a) Identify the oxidizing and reducing agents among the reactants below 2S_2O^2

Question

(a) Identify the oxidizing and reducing agents among the reactants below 2S_2O^2-_4 + TeO^2-_3 + 2OH^- times rightarrow 4SO^2-_3 + Te(s) + H_2O Dithionite Tellurite Sulfite (b) How many coulombs of charge are passed from reductant to oxidant when 1.00 g of Te is deposited? (c) If Te is created at a rate of 1.00 g/h, what is the flowing current? (d) If the electrode at which the Te is deposited has an area of 5.75 cm^2, how many mmol of Te is deposited per cm^2 of the electrode surface after one hour? What the current density of the electrode surface during this time?

Explanation / Answer

Question 1.

a)

oxidizing agent = will reduce

reducing agent = will oxidize

so

Te goes from +4 to 0, it gains 4 electrons, so it is reducing, this is the oxidizing agent

S goes from +3 to +4, it loses electrons, so it is oxidizing, therefore th ereducing agent

b)

mol of Te = masS/MW = 1/127.6 = 0.00783699 mol of Te

1 mol of Te --> 4 mol of e-

0.00783699 mol of Te --> 0.00783699*4 = 0.03134796 mol of e-

c)

rate for

charge = 96500 C per mol of e- * 0.03134796 mol of e- = 3025.07814 C

I = C/t = (3,025.07814) /(3600)= 0.840 Amps

d)

A = 5.75 cm2

find mmol of Te per cm2

so

0.00783699 mol of Te = 5.75 cm2

mol of Te per cm2 = 0.00783699/5.75 = 0.0013629 mol of Te per cm2

mmol = 0.0013629*10^3 = 1.3629 mmol of Te / Cm2

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