What is the percent composition of the alcohols I have in this solution? I have

Question

What is the percent composition of the alcohols I have in this solution? I have two unknown alcohols present. I believe that you must first figure out area % of each peak to then figure out a corrected area %, then use that to find the % composition of the two unknown alcohols. I don't really know how exactly to do that though. Please help. Thanks!

D-VAS. RUN a 183 JAN 9, 1901 03 58 35 START 629 STOP RUNE 183 JRH 9, 1901 0315B 35 AREAX AREA TYPE WIDTH AREA 1.271 119870 PH 012 12980 320 20876672 SHB 010 22.60602 29972 BP 019 03245 453 707 61891168 SPB 120 67.01802 07813 926 72151 TBP 011 174 8117 BB 020 0150 13934 BB 024 3.062 9265139 SPB 10.0326 TOTAL AREA 9.235 E.07 HUL FACTOR- 1.0000E 00 320 707 262

Explanation / Answer

To obtain a percentage composition for the mixture, first add all the peak areas. Then, to calculate the percentage of any component in the mixture, divide its individual area by the total area and multiply the result by 100.

You can determine the percent composition of the unknown alcohols from the area from the following equation:

mole % of alcohol 1= (area of the peak of alcohol 1/ total area) x 100

total area= sum of areas of all the peaks

The area of the peak is proportional to the amount ( moles ) of compound eluted. Hence, the molar percentage composition of a mixture can be approximated by comparing relative peak areas.

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