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Calculate [H3O+] given [OH] in each aqueous solution. Part A [OH] = 2.7×10 12 M

ID: 512215 • Letter: C

Question

Calculate [H3O+] given [OH] in each aqueous solution.

Part A

[OH] = 2.7×1012 M

Express your answer using two significant figures.

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Part B

Classify this solution as acidic or basic.

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Part C

[OH] = 3.0×102 M

Express your answer using two significant figures.

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Part D

Classify this solution as acidic or basic.

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Part E

[OH] = 4.6×1010 M

Express your answer using two significant figures.

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Part F

Classify this solution as acidic or basic.

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Part G

[OH] = 6.3×104 M

Express your answer using two significant figures.

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Part H

Classify this solution as acidic or basic.

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Calculate [H3O+] given [OH] in each aqueous solution.

Part A

[OH] = 2.7×1012 M

Express your answer using two significant figures.

[H3O+] =   M  

SubmitMy AnswersGive Up

Part B

Classify this solution as acidic or basic.

Classify this solution as acidic or basic. acidic basic

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Part C

[OH] = 3.0×102 M

Express your answer using two significant figures.

[H3O+] =   M  

SubmitMy AnswersGive Up

Part D

Classify this solution as acidic or basic.

Classify this solution as acidic or basic. acidic basic

SubmitMy AnswersGive Up

Part E

[OH] = 4.6×1010 M

Express your answer using two significant figures.

[H3O+] =   M  

SubmitMy AnswersGive Up

Part F

Classify this solution as acidic or basic.

Classify this solution as acidic or basic. acidic basic

SubmitMy AnswersGive Up

Part G

[OH] = 6.3×104 M

Express your answer using two significant figures.

[H3O+] =   M  

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Part H

Classify this solution as acidic or basic.

Classify this solution as acidic or basic. acidic basic

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Explanation / Answer

Ans. In an aqueous solution-

                        [H3O+] [OH-] = 10-14

            If [H3O+] > 10-7        , the solution is acidic.

            If [H3O+] < 10-7        , the solution is basic.

#A. [H3O+] = 10-14 / [OH-] = 10-14 / (2.7 x 10-12) = 3.7 x 10-3 M

#B. The solution is acidic because [H3O+] is greater than that of the same in pure water (10-7 M).

Also, pH = - log (H3O+) = - log (3.7 x 10-3) = 2.42. The solution of acidic because its pH is below 7.0 (neutral pH).

#C. [H3O+] = 10-14 / (3.0 x 10-2) = 3.3 x 10-13 M

#D. The solution is basic because [H3O+] is smaller than that of the same in pure water (10-7 M).

#E. [H3O+] = 10-14 / (4.6 x 10-10) = 2.2 x 10-5 M

#F. The solution is acidic because [H3O+] is greater than that of the same in pure water (10-7 M).

#G. [H3O+] = 10-14 / (6.3 x 10-4) = 1.6 x 10-11 M

#H. The solution is basic because [H3O+] is smaller than that of the same in pure water (10-7 M).

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