Calculate Molar volume of LAB(i and j) - Please check my calculations please! Wa

ID: 846435 • Letter: C

Question

Calculate Molar volume of LAB(i and j) - Please check my calculations please!

Wanted to make sure I'm on the right approach.

Zn(s) + 2 HCl(aq) -> ZnCl2(aq) + H2(g)

There are 6M HCl and all of them were 10.00mL volumes(same) 0.250g of zinc, and 0.500g of zinc were used in each of the trials.

(balanced)

However, I am having difficulties understanding what the calculated molar volume is suppose to be:

Trial 1

Trial 2

a) Mass of zinc used (g)

0.250g

0.500g

b) Volume of 6M HCl used (mL)

10.00mL

c) Molar mass of zinc (g/mol)

65.41

d) Moles of zinc reactant

0.0038

0.0076

e) Moles of HCl reactant (Calculate from M and V)

0.06

f) Identity of Limiting Reactant

Zinc

g) Moles of hydrogen produced calculated using stoichiometry from limiting reactant (mol)

0.0038

0.0076

h) Volume of gas produced at initial room temperature of 21.5

Zn(s) + 2 HCl(aq) -> ZnCl2(aq) + H2(g)

Molar volume is the volume of gas in liters divided by moles of hydrogen produced.

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