What is the mass (in g) of the samples? a. 25.0 moles of sulfur dioxide b. 45 mo

Question

What is the mass (in g) of the samples? a. 25.0 moles of sulfur dioxide b. 45 molecules of oxygen c. 9 billion atoms of iron d. 0.080 moles of gold(III) sulfate e. 1.00 mole of hydrogen f. 1.0 times 10^-6 moles of aluminum carbonate g. 9 billion molecules of sugar h. 9 billion molecules of octane i. 0.45 moles sodium acetate j. 1.0 times 10^20 molecules of fluorine k. 0.0090 moles of magnesium phosphate l. 400 atoms of gold m. 43.5 moles of sugar What is the percent composition by mass for each clement in the compounds? a. Lithium hydroxide b. Carbon monoxide c. Ammonium acetate d. Gold (III) sulfate e. Aluminum carbonate f. Magnesium phosphate g. Disulfur octoxide h. Octane (C_8H_18) i. Sugar (C_12H_22O_11) j. Iron(III) oxide k. Iron(II) oxide i. Copper(II) chloride m. Palladium(IV) sulfate What is the mass of each element in a 0.3155 g sample of the compounds in number 4? What is the mass (in g) of oxygen in each of the samples? a. 10.00 g of wa

Explanation / Answer

3a). 25*64=1600 gms

3b) (45/(6.023*10^23)) * 32 =2.30*10^-21 gms

3c) (9*10^9/6.023*10^23) * 56 = 8.36 * 10^-13 gms

3d) 0.08 * 682 = 54.56 gms

3e) 1*2 = 2 gms

3f) 10^-6* 234 = 2.34*10^-4 gms

3g) (9*10^9/6.023*10^23) * 342 = 4.94*10^-12 gms

3h) (9*10^9/6.023*10^23) * 114 = 1.64*10^-12 gms

3i) 0.45*82 = 36.9 gms

3j) (10^20/6.023*10^23) * 38 = 6.31 * 10^-3 gms

3k) 0.009*262.85 = 2.365 gms

3l) (400/6.023*23) *197 = 1.3*10^-19 gms

3m) 43.5* 342.29 = 14889.6 gms

According to rules I have to solve only first 4 subparts . But I solved firat 13 subparts.

Please ask separate questions.

I couldnt solve the remaining questions due to lack of time. Hope you understood.

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