Calculate the mass in kg of water produced from the combustion of 1.0 gallon (3.

Question

Calculate the mass in kg of water produced from the combustion of 1.0 gallon (3.8 L) of gasoline (C_8H_18). The density of gasoline is 0.79 g/raL. [4.2 kg H_2O] One mole of aspartame (C_14H_18N_2O_5) reacts with two moles of water to produce one mole of aspartic acid (C_4H_7NO_4), one mole of methanol (CH_3OH) and one mole of a mystery molecule. a. What is the molecular formula of the mystery molecule? b. What mass of the mystery molecule is produced from 378 g of aspartame? KO_2 is used in a closed-system breathing apparatus. It removes carbon dioxide and water from exhaled air. The reaction for the removal of water is: KO_2 + H_2O O_2 + KOH. The KOH produced is used to remove carbon dioxide by the following reaction: KOH + CO_2 rightarrow KHCO_3. a. What mass of KO_2 produces 235 g of O_2? [696 g KO_2] b. What mass of CO_2 can be removed by 123 g of KO_2? [76.1 g CO_2] In the combustion of propane (C_3H_8), if 200.0 g of propane is burned in air, how many grams of water are produced? [326.8 g H_2O] 1.000 g of an organic molecule that contains only carbon and hydrogen burns completely in the presence of excess oxygen. It yields 0.0333 mol of CO_2 and 0.599 g of H_2O. (a) Find the empirical mass of the compound. (b) The molecular mass was determined experimentally to be 84.159 g/mol. What is the molecular formula? [C_6H_12] Balance these equations, and identify the type of reaction H_2O(l) rightarrow H_2(g) + O_2(g) Zn(s) + Au(aq)^+ rightarrow Zn(aq)^2+ + Ag(s) Hydrochloric acid reacts with a solid chunk of aluminum to produce hydrogen gas and aluminum ions. Write the balanced chemical equation for this reaction. What type of reaction is this?

Explanation / Answer

Question 1.

mass of water in kg:

1 gal of gasoline

C8H18 + O2 = CO2 + H2O

balance

C8H18 + 25/2O2 = 8CO2 + 9H2O

ratio is 1 mol of gasoline = 9 mol of H2O

calculate moles of gasoliume

mass = d*V = 0.79 g/mL * 3800 mL = 3002 grams of gasoline

so

MW octane = 114.23 g/mol

mol = mass/MW = 3002/114.23 = 26.280 moles of octane

so ratio is 1:9

26.280 mol of cotne --> 9*26.280 = 236.52 moles of water

1 mol = 18 g

236.52 mol = 236.52*18 = 4257.36 g --> 4.25 kg of water

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