A student analyzing an aspirin tablet prepared a solution by dissolving 1 tablet

Question

A student analyzing an aspirin tablet prepared a solution by dissolving 1 tablet into 500 mL of solution and labeled it Solution A. The student then took 10 mL of Solution A and diluted it to 100 mL and labeled this Solution B. The student determined the acetylsalicylic acid concentration of Solution B is .000466 M.

a) What s concentration of Soltuion A.

b.)How many mg of acetylsalicylic acid are in the tablet if the Molar weight of Aspirin is 180.16 g/mol.

**Please show work/ steps-studing for a lab final**

Explanation / Answer

Ans. #A. The concertation of a solution is its intrinsic property, i.e. remains constant irrespective of the mass of solution we measure. That is, the concertation of solution A remains the same in its 10.0 mL sample as well as its 500.0 mL sample.

Now, using    C1V1 = C2V2                       

C1= Concentration, and V1= volume of initial solution 1         ; Original solution

C2= Concentration, and V2 = Volume of final solution 2         ; Diluted solution

10.0 mL (= V1) of solution A of concertation C1 (unknown) is diluted to 100.0 mL (= V2) resulting solution B with concertation of 0.000466 M (= C2).

Putting the values in above equation-

            C1 x 10.0 mL = 0.000466 M x 100.0 mL

            Or, C1 = (0.000466 M x 100.0 mL) / 10.0 mL = 0.00466 M

Therefore, concertation of solution A = 0.00466 M

#B. We concertation, concertation of solution A = 0.00466 M

Total volume of solution A (prepared from 1 tablet) = 500.0 mL = 0.500 L

Now,

Mass of acetylsalicylic acid =

Molarity x Vol. of solution in liters x Molar mass of acetylsalicylic acid

= 0.00466 M x 0.500 L x 180.16 g mol-1

                        = (0.00466 mol/ L) x 0.500 L x 180.16 g mol-1         ; [1 M = 1 mol/ L]

                        = 0.41977 g

                        = 419.77 mg                                                             ; [1 g = 1000 mg]

Therefore, amount acetylsalicylic acid in the tablet = 419.77 mg

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