1)- What volume of O2 would be required to react with excess SO2 at STP to produ
ID: 514799 • Letter: 1
Question
1)- What volume of O2 would be required to react with excess SO2 at STP to produce 0.500 moles of SO3? 2SO2(g) + O2(g) 2SO3(g) A) 22.4 L B) 33.6 L C) 11.2 L D) 44.8 L E) 5.60 L show the work please!
2)- A sample of hydrogen collected by displacement of water occupied 30.0 mL at 24.0°C on a day when the barometric pressure was 736 torr. What volume would the hydrogen occupy if it were dry and at STP? The vapor pressure of water at 24.0°C is 22.4 torr. A) 21.6 mL B) 27.6 mL C) 32.4 mL D) 36.8 mL E) 25.9 mL show the work please!
3)- A mixture of gasses containing 21.0 g of N2, 106.5 g of Cl2, and 12.0 g of Heat 21°C is in an 8.00-L container. What is the partial pressure of He? A) 9.05 atm B) 2.26 atm C) 0.647 atm D) 4.53 atm E) 5.55 atm show the work please!
Explanation / Answer
1)
Remember: 1 mol of any gas at ATP is 22.4 L
2SO2(g) + O2(g) 2SO3(g)
From reaction,
mol of O2 required = 0.5*mol of SO3
= 0.5*0.500 mol
= 0.250 mol
1 mol of O2 at STP = 22.4 L
So,
volume of O2 = number of mol * 22.4 L
= 0.250 * 22.4 L
= 5.60 L
Answer: E
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