Aspirin can be made in the laboratory by reacting acetic anhydride (C_4 H_6 O_3)
ID: 514963 • Letter: A
Question
Aspirin can be made in the laboratory by reacting acetic anhydride (C_4 H_6 O_3) with salicylic acid (C_7 H_6 O_2) to form aspirin (C_9 H_8 O_4) and acetic acid (C_2H_4O_2). The balanced equation is C_4 H_6 O_3 + C_7 H_6 O_3 rightarrow C_9 H_8 O_4 + C_2 H_4 O_2 In a laboratory synthesis, a student begins with 3.10 mL of acetic anhydride (density = 1.08 g/mL) and 1.28 g of salicylic acid. Once the reaction is complete, the student collects 1.23 g of aspirin. Determine the limiting reaction for the reaction. acetic anhydride salicylic acid Determine the theoretical yield of aspirin for the reaction Determine the percent yield of aspirin for the reaction.Explanation / Answer
C4H6O3 + C7H6O3 -------------> C9H8O4 + C2H4O2
from balanced reaction :
1 mole of acetic anhydride(C4H6O3 ) reacting with 1 mole of syllicylic acid( C7H6O3) and producing 1 mole of aspirin(C9H8O4 ) and 1 mole of acetic acide(C2H4O2)
given,
density of acetic anhydride = 1.08 g/ml
volume of of acetic anhydride = 3.10 ml
mass of acetic anhydride = density x volume
= 1.03 x 3.10
= 3.193g
Number of mole of acetic anhydride = mass / molar mass
= 3.193 / 102.09
= 0.0313 mole
mass of syliclic acid = 1.28g
number of mole of sylicylic acid = 1.28 /138.121
= 0.009267
Part A ;
The limiting reagent is the substance that is totally consumed when the chemical reaction is complete.
so ,Limiting reagent of this reaction is sylicilic acid (0.009267 mol only )
Part B;
1 mole of salicylic acid form 1mole of aspirin.
0.009267 mole of salicylic acid produce 0.009267 mole of aspirin.
mass of aspirin = number of mole x molar mass of aspirin
= 0.009267 x 180.157
= 1.669 g
Part B
mole of acetic acid formed = 0.009267
mass of acetic acid = 0.009267 x 60.05
= 0.556 g
parcent of syalicylic acid = mass of aspirin x100 / (mass of acetic acid + aspirin )
=1.669 /(0.556+1.669)
= 51.75 %
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