I can\'t seem to complete the following table. I would greatly appreciate any he

Question

I can't seem to complete the following table. I would greatly appreciate any help.

Stoichiometry and Percent Yield:

Final Weights: Trial 1: 37.806, Trial 2: 37.335, Trial 3: 37.686

Trial 3 Trial 1 Trial 2 Na2CO3 Mass of Flask (g): 36.586 36.048 36.194 Mass of Flask Na2CO3 (g): 37.886 37.452 37.414 1.3 1404 122 Mass of Na2CO3 (g): Moles of Nazcos (mo 012266 013247 011511 volume of 3 M HCl (L): Moles of HC (mol): Limiting Reactant: Theoretical Yield of NaCl (g): Mass of Flask NaCl (g Actual Yield of Cu (g) Percent Yield: Average Percent Yield Show calculations for Trial 1 below:

Explanation / Answer

From the experiment

Na2CO3 + 2HCl --> 2NaCl + CO2 + H2O

Mass of Na2CO3 = 1.3 g

moles of Na2CO3 = 1.3 g/105.99 g/mol

                              = 0.012266 mol

Volume of HCl (L) needed = 2 x 0.012266 mol/3 M

                                          = 0.0082 L

moles HCl = 0.024532 mol

Limiting reactant here would be : Na2CO3

Theoretical yield of NaCl = 0.024532 mol x 58.44 g

                                        = 1.434 g

Mass of NaCl from experiment = 37.806 - 36.586

                                                 = 1.22 g

Percent yield = 1.22 x 100/1.434

                      = 85.1%

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