Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Give the following data for each titration. Calculations The mass percentage of

ID: 515609 • Letter: G

Question

Give the following data for each titration. Calculations The mass percentage of acetic acid in vinegar is given by the expression mass % acetic acid = g acetic acid/g vinegar times 100 % (a) For each titration calculate, using Equation (16), the moles of acetic acid in the sample, (Show one complete calculation here.) Moles of acetic acid: (b) From the number of moles of acetic acid, calculate the number of grams of acetic acid for each titration. (Show one calculation here.) Mass of acetic acid: (c) Calculate the mass percentage of acetic acid for each titration. (Show one calculation here.) (If you measured the vinegar by volume rather than by weighing it, assume that the density of vinegar is 1.005 g/mL) Calculated mass% acetic acid in vinegar: (d) Calculate the average value for the three trials: _____ % If you have discarded any values, explain why. (e) What is the difference between your value and the manufacturer's stated value? Comment on the significance of this difference to you as a consumer and to the manufacturer as a producer. (f) Assuming that the density of is 1.005 g/mL calculate the molarity of acetic acid in vinegar from your average value for the mass percentage of acetic acid in vinegar.

Explanation / Answer

a) moles of acetic acid in the sample=moles of NaOH required to neutralize the acid=M(NaOH) *V(NaOH)

1)1.00M*1.3ml=1.0 mol/L*0.0013L=0.0013 moles of acetic acid

2) 1.00M*0.6ml=1.0 mol/L*0.0006L=0.0006 moles of acetic acid

3)1.00M*0.3ml=1.0 mol/L*0.0003L=0.0003 moles of acetic acid

b)grams of acetic acid=moles of acetic acid*molar mass of the acid=moles of acetic acid*60.05g/mol

1)0.0013moles*60.05g/mol=0.0781g

2)0.0006moles*60.05g/mol=0.036g

3)0.0003moles*60.05g/mol=0.018g

c)mass % of acetic acid=g acetic acid/g vinegar *100

1)mass % of acetic acid=(0.0781 g/1.0 g) *100=7.81%

2)mass % of acetic acid=(0.036 g/1.0 g) *100=3.6%

3)mass % of acetic acid=(0.018 g/1.0 g) *100=1.8%

d)average mass % of acetic acid=7.81+3.6+1.8/3=4.4%

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote