nline teaching and x G silver nitrate molar mass Goc x tltakeCovalentActivity.do
ID: 516668 • Letter: N
Question
nline teaching and x G silver nitrate molar mass Goc x tltakeCovalentActivity.do?locator assignment-take&takeAssignmentsessionLocatoraassignment-take; [Review Topics] Use the References to access important values if needed for this question. Match the following aqueous solutions with the appropriate letter from the column on the right. 1. 7.6x10 z m Al20so43. A. Highest boiling point, 2.0.14 m (NH4 2so4 B. Second highest boiling point 3, 0.12 m NiBr2 C. Third highest boiling point 4. 0.32 m Glucose(nonelectrolyte) D. Lowest boiling point 2 more group attempts remainingExplanation / Answer
Answer (2)
The freezing points of the solutions are lowered by the number of particles in solution. Each of the three salts dissociate into three ions in solution, so you multiply their molalities by 3. The nonelectrolyte does not dissociate, so its molality stays the same. The freezing points can then be ranked according to the results you obtain above. The lowest freezing point comes from the solution with the highest molality times the van't Hoff factor (3 for each salt, 1 for the ethylene glycol).
1. 0.16 m Pb(NO3)2 ------ C. Third lowest freezing point
2. 0.18 m ZnCl2----- A. Highest boiling point.
3. 0.26 m KNO3 ------ B. Second highest boiling point
4. 0.51 m Ethylene glycol--------D. Lowest boiling point
Hope this will help to you.
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