Fructose, C_6H_12O_6, is a sugar found in fruits and a source of energy for the

Question

Fructose, C_6H_12O_6, is a sugar found in fruits and a source of energy for the body. The combustion of fructose takes place according to the following equation: C_6H_12O6 (s) + 6 O_2 (g) rightarrow 6 CO_2 (g) + 6 H_2O (I) When 10.00 grams of fructose are burned in excess oxygen in a constant volume bomb calorimeter that has a heat capacity of 59.4 kJ/K, the temperature of the calorimeter increases by 1.318 K. a. Calculate the heat of the calorimeter, q_Cal. b. Calculate, by using the First Law of Thermodynamics, the heat of the reaction, q_ran. c. Let's assume that, in this experiment, Delta E = Delta H. Calculate the enthalpy of combustion (i) per gram of fructose and (ii) per mole of fructose.

Explanation / Answer

mass of fructose = 10.0 g

heat capacity of calorimeter = 59.4 kJ?k

rise in temperature = 1.318 K

a)

heat of calormeter = heat capacity x rise in temperature

= 59.4 kJ/ K x 1.318K

= 78.29 kJ

b)

From first of thermodynamics

heat absorbed by calorimeter = heat given out in combustio of substance (heat of reaction)

therefore

heat of reaction = - 78.29 kJ

part C)

assuming Delta E = Delta H

10 gof fructose on burning givs -78.29 kJ

180g /mol(1m0l) of frucose gives heat = 180 g/mol x -78.29 kJ /10g

= - 1409.2056 kJ /mol

enthalpy of combustion per mole of fructose = -1409.20 kJ/mol

enthalpy of combustion per gram = -7.829 kJ/g

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