Fructose, C_6H_12O_6, is a sugar found in fruits and a source of energy for the

Question

Fructose, C_6H_12O_6, is a sugar found in fruits and a source of energy for the body. The combustion of fructose takes place according to the following equation: C_6H_12O_6(s) + 6 O_2(g) rightarrow 6 CO_2(g) + 6 H_2O(l) When 5.00 grams of fructose are burned in excess oxygen in a constant volume bomb calorimeter that has a heat capacity of 29.7 kJ/K, the temperature of the calorimeter increases by 2.635 K. a. Calculate the heat of the calorimeter, q_Cal. b. Calculate, by using the First Law of Thermodynamics, the heat of the reaction, q_rxn. c. Let's assume that, in this experiment, delta E almostequalto delta H. Calculate the enthalpy of combustion (i) per gram of fructose and (ii) per mole of fructose.

Explanation / Answer

a)Heat absorbed by calorimeter = heat capacity x temperature difference

=29.7kJK-1 x 2.635K

= 78.2595 kJ

b) from first law of thermodynamics

heat given by reaction = heat absored by calorimeter

= -78.2595 kJ

c) assuming delta E = delta H

If 5.00g of fructose can produce 78.2595 kJ of heat on combustion

onemole(180g/mol) can produce heat = 180g/mol x 78.2595 kJ/5g

= 2817.342 kJ/mol

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